Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.
For example, given n = 3, a solution set is:
"((()))", "(()())", "(())()", "()(())", "()()()"
void help(int n, int left, int right, string cur,vector<string>& result )
{
string tmp;
if(right==n)
result.push_back(cur);
if(left<n)
{
tmp=cur+"(";
help(n, left+1, right, tmp, result);
}
if(left>right)
{
tmp = cur+")";
help(n, left, right+1, tmp, result);
}
}
vector<string> generateParenthesis(int n) {
vector<string> result;
string cur = "";
help(n, 0, 0, cur, result);
return result;
}
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