Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given
1->2->3->3->4->4->5
, return 1->2->5
.Given
1->1->1->2->3
, return 2->3
.Solution:
public ListNode deleteDuplicates(ListNode head) {
if(head == null)
return head;
ListNode root = new ListNode(0);
ListNode cur = head;
ListNode pre = root;
while(cur!=null)
{
boolean isDup = false;
while(cur.next!=null&&cur.val==cur.next.val)
{
isDup = true;
cur = cur.next;
}
if(isDup)
{
cur = cur.next;
}
else
{
pre.next = cur;
pre = cur;
cur = cur.next;
pre.next = null;
}
}
return root.next;
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