Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22
,5 / \ 4 8 / / \ 11 13 4 / \ / \ 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
void pathSumHelp(TreeNode *root, int sum, vector<int> cur,vector<vector<int> >& result )
{
if(sum-root->val==0&&!root->left&&!root->right)
{
cur.push_back(root->val);
result.push_back(cur);
return;
}
cur.push_back(root->val);
if(root->left)
{
pathSumHelp(root->left,sum-root->val,cur,result);
}
if(root->right)
{
pathSumHelp(root->right,sum-root->val,cur,result);
}
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<vector<int> > result;
if(!root)
return result;
vector<int> cur;
pathSumHelp(root,sum,cur,result);
return result;
}
{
if(sum-root->val==0&&!root->left&&!root->right)
{
cur.push_back(root->val);
result.push_back(cur);
return;
}
cur.push_back(root->val);
if(root->left)
{
pathSumHelp(root->left,sum-root->val,cur,result);
}
if(root->right)
{
pathSumHelp(root->right,sum-root->val,cur,result);
}
}
vector<vector<int> > pathSum(TreeNode *root, int sum) {
vector<vector<int> > result;
if(!root)
return result;
vector<int> cur;
pathSumHelp(root,sum,cur,result);
return result;
}
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