Leetcode: Sort Colors in C++

Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue.

Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively.

Note:

You are not suppose to use the library's sort function for this problem.
A rather straight forward solution is a two-pass algorithm using counting sort.
First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's.

Follow up:

Could you come up with an one-pass algorithm using only constant space?

Solution:

void sortColors(int A[], int n) {

        int pos0 = 0;
        int pos2 = n-1;
        int cur = 0;
        while(cur<=pos2)
        {  
            if(A[cur]==0)
            {
                swap(A[pos0],A[cur]);
                pos0++;
                cur++; // the way we do it here is because the element must be 1. Because if it is 2. we already put it into the end.
            }
            else if(A[cur]==2)
            {
                swap(A[pos2],A[cur]);
                pos2--;
            }
            else
                cur++;
        }
        
    }